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jfm
Posting Yak Master

134 Posts

Posted - 05/10/2012 :  11:02:42  Show Profile  Reply with Quote
Hi guys,

I have T1, T2

Columns that I have in those tables:

T1: A, B
T2: Z (this column whether contains info from A, B,C or D)

I need to create a new table, using the info that column Z has equal from columns A or B. Eliminating the repetitions.

Thanks!

sunitabeck
Flowing Fount of Yak Knowledge

5152 Posts

Posted - 05/10/2012 :  11:17:08  Show Profile  Reply with Quote
Not 100% sure what you are looking for, but may be this?
SELECT
	DISTINCT X INTO NewTable
FROM
	T2
	INNER JOIN T1
		ON  T2.Z = T1.A OR T2.Z = T1.B
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visakh16
Very Important crosS Applying yaK Herder

India
48076 Posts

Posted - 05/10/2012 :  11:57:17  Show Profile  Reply with Quote

SELECT t2.*
FROM T2 t2
INNER JOIN (SELECT val
            FROM T1
            UNPIVOT(val FOR Col IN ([A],[B],[C],[D]))u
           )t1
ON t1.val = t2.Z


------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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jfm
Posting Yak Master

134 Posts

Posted - 05/10/2012 :  12:09:13  Show Profile  Reply with Quote
I have:

Table1, one column called Column_ID (has the postal code of London)

Table2, two different columns:
ZIP_L
ZIP_N

But column_ID has in each cell, or ZIP_L or ZIP_N information.

What I need is a new table, that shares the info between Table1 and Table2, and give me the total output of ZIP_L and ZIP_N if is that info in Column_ID

So, I will have Column_ID, but up to the number of ZIP_L and ZIP_N info taken from Table2, and using DISCTINCT in order to eliminate the possible repetitions of the postcodes (if I have nw2, I dont want to appear nw2 as many times as I have in the previous table)

Thanks!!!!!!



I need a new table, that recognize the




DISTINCT X INTO NewTable
FROM
T2
INNER JOIN T1
ON T2.Z = T1.A OR T2.Z = T1.B[/code]
[/quote]
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visakh16
Very Important crosS Applying yaK Herder

India
48076 Posts

Posted - 05/10/2012 :  12:12:42  Show Profile  Reply with Quote

SELECT DISTINCT Column_ID INTO NewTable 
FROM Table1 t1
WHERE EXISTS (SELECT 1 FROM table2 
              WHERE ZIP_L = t1.Column_ID 
              OR ZIP_N = t1.Column_ID 
              )


------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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jfm
Posting Yak Master

134 Posts

Posted - 05/10/2012 :  12:21:30  Show Profile  Reply with Quote
Sorry visakhm,

WHERE EXISTS (SELECT 1?

thats correct?

sorry for asking, but FROM table1 t1, what is t1?

Many thanks


SELECT DISTINCT Column_ID INTO NewTable
FROM Table1 t1
WHERE EXISTS (SELECT 1 FROM table2
WHERE ZIP_L = t1.Column_ID
OR ZIP_N = t1.Column_ID
)
[/code]

------------------------------------------------------------------------------------------------------
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visakh16
Very Important crosS Applying yaK Herder

India
48076 Posts

Posted - 05/10/2012 :  12:26:10  Show Profile  Reply with Quote
quote:
Originally posted by jfm

Sorry visakhm,

WHERE EXISTS (SELECT 1?

thats correct?

sorry for asking, but FROM table1 t1, what is t1?

Many thanks


SELECT DISTINCT Column_ID INTO NewTable
FROM Table1 t1
WHERE EXISTS (SELECT 1 FROM table2
WHERE ZIP_L = t1.Column_ID
OR ZIP_N = t1.Column_ID
)
[/code]

------------------------------------------------------------------------------------------------------



Please check the query and see if it gives you intended result.

the EXISTS check ensure you return only ID from table1 which exists either in ZIP_L or ZIP_N columns of Table2. DISTINCT will avoid duplicate occurances of ID from Table1 being returned. I think that was what you asked for.

The t1 is an alias ie short name for Table1 so that you dont have repeat tablename everywhere

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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jfm
Posting Yak Master

134 Posts

Posted - 05/10/2012 :  12:33:27  Show Profile  Reply with Quote
No I cant...

The 1 next to SELECT, is correct?

Thank you visakhm

quote:
Originally posted by visakh16

quote:
Originally posted by jfm

Sorry visakhm,

WHERE EXISTS (SELECT 1?

thats correct?

sorry for asking, but FROM table1 t1, what is t1?

Many thanks


SELECT DISTINCT Column_ID INTO NewTable
FROM Table1 t1
WHERE EXISTS (SELECT 1 FROM table2
WHERE ZIP_L = t1.Column_ID
OR ZIP_N = t1.Column_ID
)
[/code]

------------------------------------------------------------------------------------------------------



Please check the query and see if it gives you intended result.

the EXISTS check ensure you return only ID from table1 which exists either in ZIP_L or ZIP_N columns of Table2. DISTINCT will avoid duplicate occurances of ID from Table1 being returned. I think that was what you asked for.

The t1 is an alias ie short name for Table1 so that you dont have repeat tablename everywhere

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/



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visakh16
Very Important crosS Applying yaK Herder

India
48076 Posts

Posted - 05/10/2012 :  15:39:08  Show Profile  Reply with Quote
quote:
Originally posted by jfm

No I cant...

The 1 next to SELECT, is correct?

Thank you visakhm

quote:
Originally posted by visakh16

quote:
Originally posted by jfm

Sorry visakhm,

WHERE EXISTS (SELECT 1?

thats correct?

sorry for asking, but FROM table1 t1, what is t1?

Many thanks


SELECT DISTINCT Column_ID INTO NewTable
FROM Table1 t1
WHERE EXISTS (SELECT 1 FROM table2
WHERE ZIP_L = t1.Column_ID
OR ZIP_N = t1.Column_ID
)
[/code]

------------------------------------------------------------------------------------------------------



Please check the query and see if it gives you intended result.

the EXISTS check ensure you return only ID from table1 which exists either in ZIP_L or ZIP_N columns of Table2. DISTINCT will avoid duplicate occurances of ID from Table1 being returned. I think that was what you asked for.

The t1 is an alias ie short name for Table1 so that you dont have repeat tablename everywhere

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/






why? whats the issue you're facing in checking it?

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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jfm
Posting Yak Master

134 Posts

Posted - 05/11/2012 :  05:36:59  Show Profile  Reply with Quote
It taking more than 50min to execute the query ...

If I execute another query, with the same data, it only takes 3 seconds.

There is not another way., to process the data?

Thanks


------------------------------------------------------------------------------------------------------

[/quote]
Please check the query and see if it gives you intended result.

the EXISTS check ensure you return only ID from table1 which exists either in ZIP_L or ZIP_N columns of Table2. DISTINCT will avoid duplicate occurances of ID from Table1 being returned. I think that was what you asked for.

The t1 is an alias ie short name for Table1 so that you dont have repeat tablename everywhere

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/


[/quote]
[/quote]
why? whats the issue you're facing in checking it?

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/


[/quote]
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visakh16
Very Important crosS Applying yaK Herder

India
48076 Posts

Posted - 05/11/2012 :  14:59:26  Show Profile  Reply with Quote
what about this?

SELECT t1.*
FROM Table1 t1
INNER JOIN (SELECT val
            FROM T1
            UNPIVOT(val FOR Col IN ([ZIP_L],[ZIP_N]))u
           )t2
ON t2.val = t1.Column_ID




------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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vinu.vijayan
Posting Yak Master

India
227 Posts

Posted - 05/14/2012 :  04:46:52  Show Profile  Reply with Quote
This could be so much easier if you could post the sample data and the Expected Result Set.

N 28° 33' 11.93148"
E 77° 14' 33.66384"
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