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Simple IF syntax help

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lcsgeek
Starting Member

USA
38 Posts

Posted - 06/29/2012 : 08:59:55

@endPercentile is a string that occasionally has a leading less-than or greater-than sign which I'm trying to strip. This code doesn't seem to be working. Can anyone give me some pointers? Thanks much.

		IF (LEFT(@endPercentile, 1) = '<' OR LEFT(@endPercentile, 1) = '>') 
		BEGIN
			SET @endPercentile = RIGHT(@endPercentile, LEN(@endPercentile)-1)
		END

webfred
Flowing Fount of Yak Knowledge

Germany
8515 Posts

Posted - 06/29/2012 : 09:15:51

declare @test varchar(255)
set @test = '<bla'
if left(@test,1) in ('<','>')
begin
stuff (@test,1,1,'')
end

No, you're never too old to Yak'n'Roll if you're too young to die.

visakh16
Very Important crosS Applying yaK Herder

India
47173 Posts

Posted - 06/29/2012 : 22:46:45

SET @endPercentile = STUFF(@endPercentile,1,CASE WHEN @endPercentile LIKE '<%' OR @endPercentile LIKE '>%' THEN 1 ELSE 0 END, '')

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

webfred
Flowing Fount of Yak Knowledge

Germany
8515 Posts

Posted - 06/30/2012 : 16:10:36

set @endPercentile = replace(left(replace(left(@endPercentile,1),'<','>'),1),'>','')

No, you're never too old to Yak'n'Roll if you're too young to die.

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