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soulchyld21
Starting Member
28 Posts |
Posted - 2012-05-30 : 05:13:24
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Hi, I am trying to return the customers that are unique in my table using this querySELECT distinct custnum, billFname, BillLName, BillPhone, BillZip FROM Mytable I am getting 40 additional records when I run this query, than when I run SELECT COUNT DISTINCT(custnum) FROM Mytable Upon further investigation I have found this is because it is treating the fields where the are slight differences, eg zipcode ad65ty and ad6 5ty as unique records (thus the customer appears twice in the returned results), any ideas on how I could structure my query to return records on distinct custnum only? (ignoring the rest of the fields eg zipcode, BillLname in the distinct part) so where there are differences like the one highlighted above the customer is only returned once!Many thanks |
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nigelrivett
Master Smack Fu Yak Hacker
3385 Posts |
Posted - 2012-05-30 : 07:23:34
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select custnum, billFname, BillLName, BillPhone, BillZipfrom (select custnum, billFname, BillLName, BillPhone, BillZip, seq = row_number() over (partition by custnum) FROM Mytable) awhere seq = 1==========================================Cursors are useful if you don't know sql.SSIS can be used in a similar way.Beer is not cold and it isn't fizzy. |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2012-05-30 : 15:52:54
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quote: Originally posted by nigelrivett select custnum, billFname, BillLName, BillPhone, BillZipfrom (select custnum, billFname, BillLName, BillPhone, BillZip, seq = row_number() over (partition by custnum order by (select null)) FROM Mytable) awhere seq = 1==========================================Cursors are useful if you don't know sql.SSIS can be used in a similar way.Beer is not cold and it isn't fizzy.
it should have an order by part------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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