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bhussey
Starting Member

5 Posts
Posted - 09/24/2012 :  15:00:33  Show Profile  Reply with Quote
I am writing a query that will show an employee age to determine if they are eligible for a certain benefit. If the employee is not 21 years of age at the time this query is run they are not eligible.

select round((sysdate-birthdate)/365.25),2
from server.table
where employee = '1234'

Result = 20.78370525642000659112226531802164930157

I'd actually like to see the Result = 20

Thank you

singularity
Posting Yak Master

149 Posts
Posted - 09/24/2012 :  15:02:22  Show Profile  Reply with Quote
You can use the floor function to round down:

http://msdn.microsoft.com/en-us/library/ms178531.aspx
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Lamprey
Flowing Fount of Yak Knowledge

3831 Posts
Posted - 09/24/2012 :  15:55:29  Show Profile  Reply with Quote
Can you just CAST the result to an INTEGER?
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bhussey
Starting Member

5 Posts
Posted - 09/24/2012 :  18:01:40  Show Profile  Reply with Quote
The floor function works, thanks for the help
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bhussey
Starting Member

5 Posts
Posted - 09/24/2012 :  18:05:35  Show Profile  Reply with Quote
I do have a additional question for this. Now I need to identify if this result is 21 or greater. I tried
(sysdate-birthdate)/365.25) >= '21' but no results
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Lamprey
Flowing Fount of Yak Knowledge

3831 Posts
Posted - 09/24/2012 :  18:58:52  Show Profile  Reply with Quote
A couple of things:

1. The FLOOR function will return the same data type as the expression being floored. What that data type is in your case, I'm not sure. It might even be a float but, I suspect it's Numeric. If it is a Float/Real, that might cause comparison issues.
2. You have wrapped the value-literal in single quotes ('21') that denotes a string. I'd have to look up the casting precedence to know for sure what SQL is doing, but that is probably your issue. You should not rely on implicit casting by SQL, rather you should explicitly cast the to the data type you want it to be.
CAST(((sysdate-birthdate)/365.25) AS INT) >= 21
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