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Mohamed Faisal
Starting Member
26 Posts |
 Posted - 10/09/2012 : 07:46:18
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I have Write an SQL query to list out details of clients who have been charged more
than $500 above the average difference for service rendered. You should have
these columns in your listing:
clientID, name, serviceCode, serviceDescription, minCharge,
averageDifference, actualServiceCost,
differenceFromAverageDifference
where differenceFromAverageDifference is the amount above the average
difference for service rendered. To qualify being selected, the
differenceFromAverageDifference for the row should be above $500.
and my tables are:
CREATE TABLE ClientTable
(
clientID char(5) NOT NULL,
clientName Char(30) NOT NULL,
clientAddress char(50) NOT NULL,
clientContact Numeric(8) NOT NULL,
CONSTRAINT ClientTablePK PRIMARY KEY(clientID),
CHECK(clientID like '[A-Z][0-9][0-9][0-9][A-Z]'),
CHECK (clientContact like '[6][0-9][0-9][0-9][0-9][0-9][0-9][0-9]' OR
clientContact like' [0-9][0-9][0-9][0-9][0-9][0-9][0-9]' OR
clientContact like'[9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]')
);
CREATE TABLE CaseTable
(
referenceNum int NOT NULL IDENTITY(100000,1),
startDate DATETIME NOT NULL,
endDate DATETIME NULL,
caseDetail Char(255) NOT NULL,
caseType Char(255) NOT NULL DEFAULT'copyright and trademark',
clientID Char(5) NOT NULL,
CONSTRAINT CaseTablePK PRIMARY KEY(referenceNum),
CONSTRAINT ClientTableFK FOREIGN KEY(clientID)
REFERENCES ClientTable(clientID),
CONSTRAINT caseTypeValues CHECK(caseType LIKE 'intellectual property enforcement' OR
caseType LIKE'copyright and trademark' OR caseType LIKE'patent and industrial design' OR
caseType LIKE'trade secret' OR caseType LIKE 'risk management' OR
caseType LIKE'litigation'),
CONSTRAINT clientIDValues CHECK(clientID LIKE '[A-Z][0-9][0-9][0-9][A-Z]')
);
CREATE TABLE ServiceTable
(
serviceCode Char(3) NOT NULL,
serviceDescription Char(255) NOT NULL,
minCharge Money NOT NULL,
CONSTRAINT ServiceTablePK PRIMARY KEY(serviceCode),
CONSTRAINT serviceCodeValues CHECK(serviceCode like '[C][0-9][0-9]' OR
serviceCode like'[E][0-9][0-9]' OR
serviceCode like'[O][0-9][0-9]'),
CONSTRAINT minChargeValues CHECK(minCharge BETWEEN '500' AND '1000000')
);
CREATE TABLE ServiceRenderedTable
(
referenceNum int NOT NULL IDENTITY(100000,1),
serviceDate DATETIME NOT NULL,
serviceCode Char(3) NOT NULL,
actualServiceCost Money NOT NULL ,
CONSTRAINT ServiceRenderedTablePK PRIMARY KEY(referenceNum,serviceDate),
CONSTRAINT CaseTableFK FOREIGN KEY(referenceNum)
REFERENCES CaseTable(referenceNum),
CONSTRAINT ServiceTableFK FOREIGN KEY(serviceCode)
REFERENCES ServiceTable(serviceCode),
CONSTRAINT actualServiceCost_positive CHECK (actualServiceCost>0.00)
);
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jabu
Starting Member
South Africa
2 Posts |
Posted - 10/09/2012 : 07:55:04
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| I would suggest that since averageDifference, actualServiceCost,differenceFromAverageDifference would be calculated values you dont have to create columns for the |
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Mohamed Faisal
Starting Member
26 Posts |
Posted - 10/09/2012 : 08:08:20
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SELECT clientID, clientName, serviceCode, serviceDescription,
minCharge, averageDifference, actualServiceCost,
(actualServiceCost - minCharge)
FROM ClientTable, [ChargeDifferences], ServiceRenderedTable
WHERE LEFT JOIN
(actualServiceCost - minCharge)>500
this is my codes. the error am getting:
Msg 156, Level 15, State 1, Line 5
Incorrect syntax near the keyword 'JOIN'.
i am sorry forgot to show my view:
CREATE VIEW ChargeDifferences
AS
SELECT S.serviceCode, S.serviceDescription, S.minCharge, AVG(SR.actualServiceCost - S.minCharge) AS averageDifference
FROM ServiceTable AS S
LEFT OUTER JOIN
ServiceRenderedTable AS SR
ON SR.serviceCode = S.serviceCode
GROUP BY S.serviceCode, S.serviceDescription, S.minCharge;
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Edited by - Mohamed Faisal on 10/09/2012 08:12:22 |
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bandi
Flowing Fount of Yak Knowledge
India
1420 Posts |
Posted - 10/09/2012 : 08:20:34
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SELECT clientID, clientName, serviceCode, serviceDescription,
minCharge, averageDifference, actualServiceCost,
(actualServiceCost - minCharge)
FROM ClientTable, [ChargeDifferences], ServiceRenderedTable
WHERE LEFT JOIN
(actualServiceCost - minCharge)>500
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Chandu |
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Mohamed Faisal
Starting Member
26 Posts |
Posted - 10/09/2012 : 08:29:50
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hi bandi,
Thanks. but i guess you need to use joins or group by for the question.
cause there is no way you can join three tables without joins or group by |
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bandi
Flowing Fount of Yak Knowledge
India
1420 Posts |
Posted - 10/09/2012 : 08:53:41
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quote:
Originally posted by Mohamed Faisal
hi bandi,
Thanks. but i guess you need to use joins or group by for the question.
cause there is no way you can join three tables without joins or group by
Try this one...
SELECT ct.clientID, clientName, srt.serviceCode, serviceDescription,
minCharge, averageDifference, actualServiceCost, (actualServiceCost - minCharge)
FROM ServiceRenderedTable srt JOIN [ChargeDifferences] cd ON srt.serviceCode = cd.serviceCode
JOIN CaseTable ct ON ct.referenceNum = srt.referenceNum
JOIN ClientTable clt ON clt.clientID = ct.clientID
WHERE (actualServiceCost - minCharge)>500;
In your question you have asked for 'differenceFromAverageDifference'. what it means?
But you are calculating (actualServiceCost - minCharge).
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Chandu |
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Mohamed Faisal
Starting Member
26 Posts |
Posted - 10/09/2012 : 09:03:08
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Hi bandi,
Thanks, for the differenceFromAverageDifference is the amount above the average difference(averageDifference) for service rendered. To qualify being selected, the differenceFromAverageDifference for the row should be above $500. so i guessing that the (averageDifference)must be above 500. |
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bandi
Flowing Fount of Yak Knowledge
India
1420 Posts |
Posted - 10/09/2012 : 09:10:54
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quote:
Originally posted by Mohamed Faisal
Hi bandi,
Thanks, for the differenceFromAverageDifference is the amount above the average difference(averageDifference) for service rendered. To qualify being selected, the differenceFromAverageDifference for the row should be above $500. so i guessing that the (averageDifference)must be above 500.
Welcome 
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Chandu |
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need some help
