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yellowman
Starting Member

USA
25 Posts
Posted - 11/12/2012 :  15:52:09  Show Profile  Reply with Quote

I keep trying to run the piece of code below on one of my databases and I am getting and error that says the following:

Msg 170, Level 15, State 1, Line 1
Line 1: Incorrect syntax near '8000'.

Any ideas? Its probably something simple that I am overlooking (like a missing tick somewhere).


DECLARE @Database varchar(100)
DECLARE @Command nvarchar(200)
SELECT @Database = 'Bank_PROD'
SELECT @Command = 'SELECT ' +@Database+ ' AS dbname,Left(SUBSTRING(dbo.program, PATINDEX(''%[0-9.-]%'', dbo.program), 8000), PATINDEX(''%[^0-9.-]%'', SUBSTRING(dbo.program, PATINDEX(''%[0-9.-]%'', dbo.program), 8000) + ''X'')-1) AS Schema_Version
FROM ' +@Database + '.dbo.scriptdef
WHERE (dbo.program LIKE ''%sub schema_Version%'')'
EXEC(@Command)

sunitabeck
Flowing Fount of Yak Knowledge

5152 Posts
Posted - 11/12/2012 :  16:01:22  Show Profile  Reply with Quote
Your query does not have a FROM clause even though the SELECT clause refers to column names. You will see what I mean if you print out the dynamic SQL.
...
WHERE (dbo.program LIKE ''%sub schema_Version%'')'
PRINT @Command
EXEC(@Command)
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yellowman
Starting Member

USA
25 Posts
Posted - 11/12/2012 :  16:13:32  Show Profile  Reply with Quote
I forgot about the PRINT command for debugging......thanks.

Looks like this piece got truncated:

+ ''X'')-1) AS Schema_Version
FROM ' +@Database + '.dbo.scriptdef
WHERE (dbo.program LIKE ''%sub schema_Version%'')'

Does the + sign get some sort of special treatment when its a string literal?
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Lamprey
Flowing Fount of Yak Knowledge

3833 Posts
Posted - 11/12/2012 :  16:47:31  Show Profile  Reply with Quote
You need to make your variable for the Command larger, if you select the LEN of the variable you will see that it is full (200):
DECLARE @Database varchar(100)
DECLARE @Command nvarchar(200)
SELECT @Database = 'Bank_PROD'
SELECT @Command = 'SELECT ' +@Database+ ' AS dbname,Left(SUBSTRING(dbo.program, PATINDEX(''%[0-9.-]%'', dbo.program), 8000), PATINDEX(''%[^0-9.-]%'', SUBSTRING(dbo.program, PATINDEX(''%[0-9.-]%'', dbo.program), 8000) + ''X'')-1) AS Schema_Version
FROM ' +@Database + '.dbo.scriptdef
WHERE (dbo.program LIKE ''%sub schema_Version%'')'

SELECT LEN(@Command)
PRINT(@Command)
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yellowman
Starting Member

USA
25 Posts
Posted - 11/12/2012 :  16:57:31  Show Profile  Reply with Quote
I can't believe I overlooked the most obvious. I didn't even think to look at that. Thanks so much for the help.
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