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Query Upcoming Weekend Only

Author

Topic

mattie
Starting Member

13 Posts

Posted - 2012-12-14 : 12:57:38

I have a field called Sched_Date that I use in a Case Statement: Case When datepart (weekday, SCHED_DATE) = 1 Then 'Sunday' When datepart (weekday, SCHED_DATE) = 7 Then 'Saturday' End as Weekend

I want to be able to only include the sched_Date for the upcoming Weekend in the Where Clause, and include both Saturday and Sunday. I would like it to run automatically, so I don't have to rewrite the dates each time.

Is this possible? Thx

sunitabeck
Master Smack Fu Yak Hacker

5155 Posts

Posted - 2012-12-14 : 13:16:26

You can do the following. Check the boundary conditions though - like, if today is a Sunday, do you want to consider the following Saturday as a weekend or not etc.

SELECT CASE 
            WHEN CASE 
                      WHEN DATEPART(weekday, c) = 1 THEN 'Sunday'
                      WHEN DATEPART(weekday, SCHED_DATE) = 7 THEN 'Saturday'
                 END 
                 AND DATEDIFF(dd, GETDATE(), SCHED_DATE) > 6 THEN 1
            ELSE 0
       END AS Weekend

A bit shorter code that is also language independent is as follows:

SELECT CASE 
            WHEN DATEDIFF(dd, 0, SCHED_DATE)%7 > 4 
                 AND DATEDIFF(dd, GETDATE(), SCHED_DATE) > 6 THEN 1
            ELSE 0
       END AS Weekend

mattie
Starting Member

13 Posts

Posted - 2012-12-14 : 13:39:42

Yes, when the query is run on Saturday or Sunday, I would like it to query the CURRENT Weekend. When it's any other day, the following weekend. Is there a way to do this in the Where Clause without the CASE? I keep getting syntax errors when I try this.

sunitabeck
Master Smack Fu Yak Hacker

5155 Posts

Posted - 2012-12-14 : 13:55:53

I am not seeing any syntax error in the code that I posted. Can you post the code that you are seeing the error in and also the error message?

shilpash
Posting Yak Master

103 Posts

Posted - 2012-12-14 : 13:56:53

SELECT MAX(SCHED_DATE)
,DATEPART(weekday,SCHED_DATE)
FROM TABLENAME
WHERE DATEPART(weekday,SCHED_DATE) = 7
OR DATEPART(weekday,SCHED_DATE) = 1
GROUP BY DATEPART(weekday,SCHED_DATE)

sunitabeck
Master Smack Fu Yak Hacker

5155 Posts

Posted - 2012-12-14 : 14:07:30

quote:
Originally posted by shilpash

SELECT MAX(SCHED_DATE)
,DATEPART(weekday,SCHED_DATE)
FROM TABLENAME
WHERE DATEPART(weekday,SCHED_DATE) = 7
OR DATEPART(weekday,SCHED_DATE) = 1
GROUP BY DATEPART(weekday,SCHED_DATE)

I am not seeing any syntax error in this code. Can you post the error message you are getting?

mattie
Starting Member

13 Posts

Posted - 2012-12-14 : 14:43:33

The last post seemed to work, but it shows all the weekends in December, instead of just the following weekend, i.e. 12/15 and 12/17. Thx!

sunitabeck
Master Smack Fu Yak Hacker

5155 Posts

Posted - 2012-12-14 : 14:47:36

quote:
Originally posted by mattie

The last post seemed to work, but it shows all the weekends in December, instead of just the following weekend, i.e. 12/15 and 12/17. Thx!

True, it would do that - but you did not include the additional condition in the where clause that I had suggested. Add that as well.

mattie
Starting Member

13 Posts

Posted - 2012-12-14 : 15:01:48

Can you tell me what I'm missing in the following? Thx for your help.

Select MAX(Sched_Date) , datepart (weekday, SCHED_DATE) as Day_Week
From Table

where
(DATEPART(weekday,SCHED_DATE) = 7
OR DATEPART(weekday,SCHED_DATE) = 1)

GROUP BY DATEPART(weekday,SCHED_DATE)

sunitabeck
Master Smack Fu Yak Hacker

5155 Posts

Posted - 2012-12-14 : 15:07:48

[code]SELECT MAX(Sched_Date),
DATEPART(weekday, SCHED_DATE) AS Day_Week
FROM tbl
WHERE (
( DATEPART(weekday, SCHED_DATE) = 7
OR DATEPART(weekday, SCHED_DATE) = 1
) AND DATEDIFF(dd, GETDATE(), SCHED_DATE) > 6
)
GROUP BY
DATEPART(weekday, SCHED_DATE)
[/code]

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2012-12-14 : 15:14:01

for just getting following weekend this is enough


SELECT MAX(SCHED_DATE)
,DATEPART(weekday,SCHED_DATE)
FROM TABLENAME
WHERE SCHED_DATE >=DATEADD(day,(DATEDIFF(day,0,GETDATE())/7) * 7,5)
AND SCHED_DATE < DATEADD(day,(DATEDIFF(day,0,GETDATE())/7) * 7,7)
GROUP BY DATEPART(weekday,SCHED_DATE)

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2012-12-14 : 15:14:51

also make sure you read this

http://visakhm.blogspot.in/2012/08/creating-server-independent-day.html

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

mattie
Starting Member

13 Posts

Posted - 2012-12-14 : 16:35:04

This worked great. Reading article also now. Thx to both of you.

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2012-12-15 : 12:18:58

welcome

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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