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Posting Yak Master

172 Posts

Posted - 09/14/2013 :  12:04:32  Show Profile  Reply with Quote
We have to value, birth date and today date.
How can we calculate years, months and days after a date (old age)?

for example according to following values(yyyymmdd) we need these values:
12 years - 10 months - 2 days

select '2000-05-29' as bithdate,'2013-04-01' as today_date

Please direct me.

Edited by - sigmas on 09/14/2013 12:08:50

Aged Yak Warrior

549 Posts

Posted - 09/14/2013 :  14:50:08  Show Profile  Reply with Quote
Something like this:

SELECT '2000-05-29' as bithdate,'2013-04-01' as today_date,  
	DATEPART(YEAR, DATEADD(DAY, 0, DATEDIFF(DAY, '2000-05-29','2013-04-01'))) - 1900 AS [YEARS],
	DATEPART(MONTH, DATEADD(DAY, 0, DATEDIFF(DAY, '2000-05-29','2013-04-01')))-1 AS [MONTHS],
	DATEPART(DAY, DATEADD(DAY, 0, DATEDIFF(DAY, '2000-05-29','2013-04-01')))-1 AS [DAYS];

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Posting Yak Master

172 Posts

Posted - 09/15/2013 :  15:02:32  Show Profile  Reply with Quote
Thank you very much.
I think no need to DATEADD function. It automatically calculate adding the days with base date.

	DATEPART(YEAR, DATEDIFF(DAY, bithdate,today_date)) - 1900 AS [YEARS],
	DATEPART(MONTH, DATEDIFF(DAY, bithdate,today_date))-1 AS [MONTHS],
	DATEPART(DAY, DATEDIFF(DAY, bithdate,today_date))-1 AS [DAYS],
	DATEPART(DAY, DATEDIFF(DAY, bithdate,today_date))-1 AS [DAYS]
VALUES('2000-05-31', '2013-04-01'),--12-10-2
)D (bithdate, today_date);
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In (Som, Ni, Yak)

17684 Posts

Posted - 09/16/2013 :  00:01:41  Show Profile  Reply with Quote
See "Finding Age" in this thread http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=64762&SearchTerms=Finding%20Age

Time is always against us

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