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 replace nth occurrence with blank
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Posting Yak Master

154 Posts

Posted - 09/20/2013 :  18:07:32  Show Profile  Reply with Quote
How do replace the 2nd occurrence of a character with an empty string? Example "1234/00/11/123456" would become "1234/0011/123456"

Posting Yak Master

172 Posts

Posted - 09/20/2013 :  22:37:25  Show Profile  Reply with Quote
declare @v varchar(50) = '1234/00/11/123456'

select stuff(@v,charindex('/',@v,charindex('/',@v)+1),1,'');
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