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 Transact-SQL (2008)
 Generate a number list from a string value
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Starting Member

7 Posts

Posted - 10/22/2013 :  16:28:51  Show Profile  Reply with Quote
I have a single column that has string values like ['61000-61055']. I am trying to get the list of numbers that would start with 61000, and end with 61055. The actual data has the beginning and ending quotes as part of the string. My output would have a number on each row.

Using SQL Server 2008 R2


James K
Flowing Fount of Yak Knowledge

3873 Posts

Posted - 10/22/2013 :  16:52:38  Show Profile  Reply with Quote
Are all the rows in the table consistently of the same pattern - i.e., a left square bracket, followed by a single quote, followed by a number, followed by a hyphen, followed by a number then single quote and square bracket?

Edited by - James K on 10/22/2013 16:52:50
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Starting Member

7 Posts

Posted - 10/22/2013 :  18:39:52  Show Profile  Reply with Quote
They are all consistent with a single quote, number, hyphen, number, then single quote'
exp. '61000-61055'

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Very Important crosS Applying yaK Herder

52326 Posts

Posted - 10/23/2013 :  02:07:51  Show Profile  Reply with Quote

SELECT StartVal + v.number
SELECT REPLACE(LEFT(Col,CHARINDEX('-',Col)-1),'[''','') AS StartVal,
REPLACE(STUFF(Col,1,CHARINDEX('-',Col),''),''']','') AS EndVal
FROM table 
CROSS JOIN master..spt_values v
WHERE v.type = 'p'
AND StartVal + v.number <= EndVal

SQL Server MVP
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Starting Member

7 Posts

Posted - 10/23/2013 :  16:42:40  Show Profile  Reply with Quote

I'll give that a try.
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