triming leading and trailing zeros

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triming leading and trailing zeros

Author

Topic

scelamko
Constraint Violating Yak Guru

309 Posts

Posted - 2005-03-30 : 13:55:06

guys,
how do I trim leading zeros and trailing zeros from column values.
Apparently ltrim and rtrim works only with the whitespaces.
do we have any function that acheive this.

any suggestions/input will be apprecited

Thanks

JimL
SQL Slinging Yak Ranger

1537 Posts

Posted - 2005-03-30 : 14:19:17

You can trim leading by converting into INT.

How about some sample data and senarios.

Jim
Users <> Logic

scelamko
Constraint Violating Yak Guru

309 Posts

Posted - 2005-03-30 : 14:49:02

I have a scenario of column with datatype char(9) and which has data similar to the following
000P34566
00KP43434

So since the column datatype is char and since there is inconsistency at the number leading zero
that the column value may have, this is making the things all the more diffcult for me

any suggestions/inputs/work arounds would be helpful indeed.

thanks

JimL
SQL Slinging Yak Ranger

1537 Posts

Posted - 2005-03-30 : 15:12:16

You can use case and substring

select
mycolumn = case when Substring(mycolumn,1,4) = '0000'
Then Substring(mycolumn,5,5)
when Substring(mycolumn,1,3) = '000'
Then Substring(mycolumn,4,6)
when Substring(mycolumn,1,2) = '00'
Then Substring(mycolumn,3,7)
when Substring(mycolumn,1,1) = '0'
Then Substring(mycolumn,2,8)
else mycolumn
end
From mytable

Jim
Users <> Logic

SwePeso
Patron Saint of Lost Yaks

30421 Posts

Posted - 2006-06-17 : 08:32:34

[code]-- prepare test data
declare @num table (i varchar(50))

insert @num
select '000P123450000' union all
select '000C342344004564123490000' union all
select '0000000000KP32100'

-- do the work
SELECT i,
patindex('%[^0]%', i),
patindex('%[^0]%', reverse(i)),
substring(i, patindex('%[^0]%', i), 2 + len(i) - patindex('%[^0]%', i) - patindex('%[^0]%', reverse(i)))
FROM @num[/code]
Peter Larsson
Helsingborg, Sweden

Michael Valentine Jones
Yak DBA Kernel (pronounced Colonel)

7020 Posts

Posted - 2006-06-17 : 14:00:29

Trim leading and trailing zeros from strings:


elect
	x,
	[Trimmed X] =
	left(replace(replace(rtrim(ltrim(replace(replace(
	x,' ','#'),'0',' '))),' ','0'),'#',' '),15)
from
	(
	select x='000P34566' union all
	select x='600P34500' union all
	select x='000P34000' union all
	select x='00KP 3434'
	) a

Results:



x         Trimmed X       
--------- --------------- 
000P34566 P34566
600P34500 600P345
000P34000 P34
00KP 3434 KP 3434

(4 row(s) affected)

CODO ERGO SUM

madhivanan
Premature Yak Congratulator

22864 Posts

Posted - 2006-06-19 : 04:48:26

quote:
Originally posted by scelamko

I have a scenario of column with datatype char(9) and which has data similar to the following
000P34566
00KP43434

So since the column datatype is char and since there is inconsistency at the number leading zero
that the column value may have, this is making the things all the more diffcult for me

any suggestions/inputs/work arounds would be helpful indeed.

thanks

MVJ has missed S in Select

Other method. Refer this
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=56713

Madhivanan

Failing to plan is Planning to fail

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