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                                         vasu4us 
                                        Posting Yak  Master 
                                         
                                        
                                        102 Posts  | 
                                        
                                        
                                            
                                            
                                             Posted - 2006-08-30 : 08:45:14
                                            
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                                            | i have 2 tables with a common ID in both tables.one table has more number of rows than the otheri want to a query which gives the list of ids or rows which are missing in the other table.left,right,inner jopins only give me common or common + right/lefti want only the missing once.can someone help me with this | 
                                             
                                         
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                                     SwePeso 
                                    Patron Saint of Lost Yaks 
                                     
                                    
                                    30421 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2006-08-30 : 08:50:28
                                          
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                                          | TableA has the "more number" records.SELECT TableA.*FROM TableALEFT JOIN TableB ON TableB.ID = TableA.IDWHERE TableB.ID IS NULLPeter LarssonHelsingborg, Sweden  | 
                                         
                                        
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                                     harsh_athalye 
                                    Master Smack Fu Yak Hacker 
                                     
                                    
                                    5581 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2006-08-30 : 09:41:34
                                          
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                                          or this....SELECT * FROM TABLEA X WHERE NOT EXISTS (SELECT * FROM TABLEB Y WHERE Y.ID = X.ID) Harsh AthalyeIndia."Nothing is Impossible"  | 
                                         
                                        
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                                     vasu4us 
                                    Posting Yak  Master 
                                     
                                    
                                    102 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2006-08-30 : 11:03:39
                                          
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                                          | thanks two solutions worked but when i count the 2 tables the difference is 10006 rowsbut when i run this query iam geting 12310 rows. iam not able to justify why this difference  | 
                                         
                                        
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                                     SwePeso 
                                    Patron Saint of Lost Yaks 
                                     
                                    
                                    30421 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2006-08-30 : 11:40:15
                                          
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                                          | You most probably have duplicate IDs somewhere.SELECT COUNT(DISTINCT ID), COUNT(ID) FROM TableASELECT COUNT(DISTINCT ID), COUNT(ID) FROM TableBPeter LarssonHelsingborg, Sweden  | 
                                         
                                        
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