declare @d datetime
set @d='2100-01-01'
Select 
	case   
		when year(@d)%400=0 then 'yes'
		when year(@d)%100=0 then 'no'
		when year(@d)%4=0 then 'yes'
	else 'no'  
	end 
as is_leap_year

select
	YEAR,
	IS_LEAP_YEAR =
	-- If 60th day of the year is in February, then it's leap year.
	case month(dateadd(yy,a.YEAR-1900,0)+59) when 2 then 'yes' else 'no' end
from
	(
	select YEAR = 1800	union all
	select YEAR = 1900	union all
	select YEAR = 2000	union all
	select YEAR = 2001	union all
	select YEAR = 2002	union all
	select YEAR = 2003	union all
	select YEAR = 2004	union all
	select YEAR = 2005	union all
	select YEAR = 2006	union all
	select YEAR = 2007	union all
	select YEAR = 2008	union all
	select YEAR = 2009	union all
	select YEAR = 2010	union all
	select YEAR = 2011	union all
	select YEAR = 2400
	) a


Results:

YEAR        IS_LEAP_YEAR 
----------- ------------ 
1800        no
1900        no
2000        yes
2001        no
2002        no
2003        no
2004        yes
2005        no
2006        no
2007        no
2008        yes
2009        no
2010        no
2011        no
2400        yes

(15 row(s) affected)

quote:

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Originally posted by rauof_thameem

Thanks Mahadi

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quote:

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Originally posted by anki0121

This is very simple....
select (case to_number(to_char((trunc(to_date('15/08/08','dd/mm/yy'),'yy')+59),'mm')) when 2 then 'Yes' else 'No' end) as yr
from dual

here I have first found the first day of the year
which can be done by using
Select Trunc(To_date(SYSDATE),'yy')
from dual


and then adding 59 days to it and then using the case statement to check whether the month is 2 or 3 depending on which leap year can be found out

When u need someone...
Ankeyzzzz always dere

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