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Loops

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AskSQLTeam
Ask SQLTeam Question

0 Posts

Posted - 2004-04-20 : 10:05:23

Lois writes "I have a start date and end date. Each date is passed into a function that returns the first day of the week (ex. 04/08/2004 would return 04/04/2004). This same function does the exact return for the end date.

I need to take the start date and add one day to it so it will return not only the start date of 04/04/2004 but then increment the date by 1 day so the next date would be 04/05/2004 and this would go on until it reaches the end date which let's say is 05/02/2004. So my dates would go something like this 04/04/2004, 04/05/2004, 04/06/204, 04/07/2004, etc. I need to put them into a tmp table.

My question to you is how do I write a loop that will look at the variable startdate then do the dateadd(d, 1, startdate) and continue until it reached the enddate.

I will be placing each incremented date into a tmp table.

The table structure I am using only has one date field and I need to break out the date into a day by day listing.

Thank you for any assistance."

ditch
Master Smack Fu Yak Hacker

1466 Posts

Posted - 2004-04-20 : 10:29:22

Something Like This:

CREATE TABLE #DateTab(DateField DATETIME)

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME

SET @StartDate = '2004-04-01'
SET @EndDate = '2004-04-04'

WHILE @StartDate <= @EndDate
BEGIN
INSERT INTO #DateTab SELECT @StartDate
SET @StartDate = DATEADD(d, 1, @StartDate)
END

SELECT * FROM #DateTab

Duane.

cas_o
Posting Yak Master

154 Posts

Posted - 2004-04-20 : 10:40:33

Use the WHILE loop eg:

declare @startdate datetime, @enddate datetime, @middledate datetime
select @startdate = exec datefunction @startdate
select @enddate = exec datefunction @enddate
select @middledate = dateadd(d,1,@startdate)

while @middledate < @endate
begin
insert into temptable @middledate
select @middledate = dateadd(d,1,@middledate)
end

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