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AskSQLTeam
Ask SQLTeam Question
0 Posts |
Posted - 2004-05-26 : 07:01:03
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| Suman writes "I need to search for a string with a column; but first I need to strip-out some characters (say every fifth character) before I can compare the user passed string with the stored data (the table has about 500000 records). I’m running SQL Server 7 and unable to use a UDF.Here is an example:Table:Column1 Column2 ColumnN1 1234567890 xxxxx2 1111111111 xxxxx3 1234567899 xxxxxNow I want to search for ‘12346789’ using logic where I can ignore the every fifth character from ‘Column2’ before I search for ‘1236789’. The result should return the first and the last column.Any help or suggestion is greatly appreciated." |
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sorengi
Starting Member
48 Posts |
Posted - 2004-05-26 : 14:44:07
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| SELECT Column2FROM TestWHERE left(Column2,4) + right(Column2,5) like '%12346789%'Michael D. |
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