Select	e.*
From	(
	Select	employeeID
		,ProjectCount = count(*) --count(distinct ProjectID) --if employeeid/projectid combinations are not unique
	From	employeeProject
	Group by employeeID
	having count(*) = (Select count(*) projectCount from Project)
	) as epc
JOIN	Employee e
		ON epc.employeeID = e.employeeID


Select	e.*
From	(--Get employees NOT in subquery results
	Select	distinct ep1.EmployeeID
	From	EmployeeProject ep1
	Left JOIN (--Get employees that have NOT worked on all projects
		Select	ep2.employeeID
		From	Project p2
		Left JOIN EmployeeProject ep2
				on p2.projectID = ep2.projectID
		Where	ep2.projectID is NULL
		) as empExcl
			ON empExcl.employeeID = ep1.employeeID
	Where	empExcl.employeeID is NULL
	) as empIncl
JOIN	Employee e
		ON e.employeeID = empIncl.employeeID