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AskSQLTeam
Ask SQLTeam Question
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Posted - 2006-06-15 : 08:24:53
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| priya writes "select convert(smalldatetime,'09/06/2006') is workingselect convert(smalldatetime,'13/06/2006') it shows an errorThe conversion of char data type to smalldatetime data type resulted in an out-of-range smalldatetime value.why it shows an error" |
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robvolk
Most Valuable Yak
15732 Posts |
Posted - 2006-06-15 : 08:26:54
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| It's assuming an American date format (mm/dd/yyyy) but your dates are British format (dd/mm/yyyy). The first conversion succeeded but it returned the wrong date. Try this:select convert(smalldatetime,'13/06/2006', 103)select convert(smalldatetime,'09/06/2006', 103) |
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