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Zcumbag
Starting Member
3 Posts |
Posted - 2007-02-23 : 17:52:49
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| Hi.I was wondering how I should go about doing this thing. I need to put a value in a column that is based on values on other columns in the same row.insert into myTable(Col1, Col2)values(25, -14)When this statement executes I need to put a value in Col3. Like:if(Col1 >0 AND Col2 <0) set Col3 = Col1 - Col2else set Col3 = Col1;I don't now quite how to solve this. I am really going to need this value in a column. Calculating the value at retrieval is not on option...I appreciate all help.Thanks! |
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2007-02-23 : 20:38:11
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[code]declare @col1 int, @col2 intselect @col1 = 25, @col2 = -14insert into myTable (Col1, Col2, Col3)select @col1, @col2, case when @col1 > 0 and @col2 < 0 then @col1 - @col2 else @col1 end[/code] KH |
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mahesh_bote
Constraint Violating Yak Guru
298 Posts |
Posted - 2007-02-27 : 05:52:30
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quote: Originally posted by khtan
declare @col1 int, @col2 intselect @col1 = 25, @col2 = -14insert into myTable (Col1, Col2, Col3)select @col1, @col2, case when @col1 > 0 and @col2 < 0 then @col1 - @col2 else @col1 end KH
khtan, i think he wants to update into the table. hopes this will workupdate test set col3 = case when col1 > 0 and col2 < 0 then col1 - col2 else col1 endwhere col1 = <value>thanks,Mahesh |
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harsh_athalye
Master Smack Fu Yak Hacker
5581 Posts |
Posted - 2007-02-27 : 06:06:55
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quote: Originally posted by mahesh_bote
quote: Originally posted by khtan
declare @col1 int, @col2 intselect @col1 = 25, @col2 = -14insert into myTable (Col1, Col2, Col3)select @col1, @col2, case when @col1 > 0 and @col2 < 0 then @col1 - @col2 else @col1 end KH
khtan, i think he wants to update into the table. hopes this will workupdate test set col3 = case when col1 > 0 and col2 < 0 then col1 - col2 else col1 endwhere col1 = <value>thanks,Mahesh
Why UPDATE? When you can do it while inserting itself !Harsh AthalyeIndia."The IMPOSSIBLE is often UNTRIED" |
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