create function dbo.F_START_OF_WEEK
(
	@DATE			datetime,
	-- Sun = 1, Mon = 2, Tue = 3, Wed = 4
	-- Thu = 5, Fri = 6, Sat = 7
	-- Default to Sunday
	@WEEK_START_DAY		int	= 1	
)
/*
Find the fisrt date on or before @DATE that matches 
day of week of @WEEK_START_DAY.
*/
returns		datetime
as
begin
declare	 @START_OF_WEEK_DATE	datetime
declare	 @FIRST_BOW		datetime

-- Check for valid day of week
if @WEEK_START_DAY between 1 and 7
	begin
	-- Find first day on or after 1753/1/1 (-53690)
	-- matching day of week of @WEEK_START_DAY
	-- 1753/1/1 is earliest possible SQL Server date.
	select @FIRST_BOW = convert(datetime,-53690+((@WEEK_START_DAY+5)%7))
	-- Verify beginning of week not before 1753/1/1
	if @DATE >= @FIRST_BOW
		begin
		select @START_OF_WEEK_DATE = 
		dateadd(dd,(datediff(dd,@FIRST_BOW,@DATE)/7)*7,@FIRST_BOW)
		end
	end

return @START_OF_WEEK_DATE

end

quote:

---

Originally posted by Peso

You could follow the link above, and copy the code for the user defined function to new query window and run the code.
Then empty the code window and run

select dbo.F_START_OF_WEEK(getdate() + 7, 2) as nextmonday, dbo.F_START_OF_WEEK(getdate() + 7, 6) as nextfriday


Peter Larsson
Helsingborg, Sweden

---

select
	dbo.F_START_OF_WEEK(getdate()+7,1)+1 as NextMonday, 
	dbo.F_START_OF_WEEK(getdate()+7,1)+5 as NextFriday

NextMonday              NextFriday 
----------------------- -----------------------
2007-04-02 00:00:00.000 2007-04-06 00:00:00.000

(1 row(s) affected)

select
	dbo.F_START_OF_WEEK(getdate()+8,2) as NextMonday, 
	dbo.F_START_OF_WEEK(getdate()+12,6) as NextFriday