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Filaci
Starting Member
2 Posts |
Posted - 2007-05-13 : 16:41:09
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| HelloI have a table from cars GPS positions:CREATE TABLE Positions (Ident VARCHAR(20) NOT NULL,Valid BOOL,Date DATETIME NOT NULL,Latitude FLOAT,Longitude FLOAT,Speed INT}Sorry about the poor english... :)I like select the last position where Ident=DEMO1 and DEMO2....How can I make that?Practically I sould like to now, where is the last positions of selected cars!I try this, but not good:SELECT MAX(date), ident, latitude, longitude, speedFROM positionsWHERE valid=1 && (ident='DEMO1' || ident='DEMO2'|| ident='DEMO3')GROUP BY ident;I get 3 record, the dates is the last, but the lat. and long. is wrong...Thanks,Laci |
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Kristen
Test
22859 Posts |
Posted - 2007-05-13 : 16:46:52
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Perhaps this is what you are after?SELECT [date], P.ident, latitude, longitude, speedFROM positions AS P JOIN ( SELECT ident, MAX(date) AS [MAX_Date] FROM positions WHERE valid=1 AND ident IN ('DEMO1', 'DEMO2', 'DEMO3') GROUP BY ident ) AS X ON X.ident = P.ident AND X.MAX_Date = P.[date]WHERE valid=1 AND P.ident IN ('DEMO1', 'DEMO2', 'DEMO3')Kristen |
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Filaci
Starting Member
2 Posts |
Posted - 2007-05-13 : 17:18:18
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| Thanks for quick answer!The subselect work perfectly, but the entire select has 0 rows result.I now use this solution, but in PHP must execute in loop, many times as idents:(I use ident translation, the user view the licence plate number, not the ident...)foreach($_GET as $rsz){ $eredmeny = mysql_query(' SELECT datum, //date poziciok.keszulekaz, //ident szelesseg, //lat hosszusag, //long bemenet1, elnevezes //name FROM poziciok //positions LEFT JOIN elnevezesek //names ON elnevezesek.keszulekaz = poziciok.keszulekaz AND elnevezesek.felhasznalonev = \''.$_SESSION['LoginNev'].'\' //username WHERE poziciok.keszulekaz = \''.$rsz.'\' && valid = 1 ORDER BY datum DESC LIMIT 0,1 ');..//mysql_fetch_array....}This solution is very slow.... Laci |
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SwePeso
Patron Saint of Lost Yaks
30421 Posts |
Posted - 2007-05-14 : 02:15:03
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| This forum is for Microsoft SQL Server questions.PHP and/or MySQL questions are better answered at www.dbforums.comPeter LarssonHelsingborg, Sweden |
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Kristen
Test
22859 Posts |
Posted - 2007-05-14 : 02:17:54
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| Does MySql even support a nested sub-select like that these days? |
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madhivanan
Premature Yak Congratulator
22864 Posts |
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