not display the letter unless count >= 3

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not display the letter unless count >= 3

Author

Topic

argon007
Starting Member

38 Posts

Posted - 2008-06-03 : 23:46:23

[code]SELECT name = SUBSTRING(name, 1, 1),
total = COUNT(SUBSTRING(name, 1, 1))
FROM products
GROUP BY SUBSTRING(name, 1, 1)[/code]

the assignment said that,

quote:
"Do not display the letter and count unless at least three product names begin with the letter."

but i got the errors when I try following.

[code]WHERE total >= 3[/code]

quote:
Msg 207, Level 16, State 1, Line 4
Invalid column name 'total'.

[code]WHERE COUNT(SUBSTRING(name, 1, 1)) >= 3[/code]

quote:
Msg 147, Level 15, State 1, Line 1
An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

so what should I do?

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2008-06-03 : 23:49:40

SELECT name = SUBSTRING(name, 1, 1),
total = COUNT(SUBSTRING(name, 1, 1))
FROM products
GROUP BY SUBSTRING(name, 1, 1)
HAVING COUNT(SUBSTRING(name, 1, 1)) >= 3

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2008-06-03 : 23:50:53

The error message clearly suggested the use of HAVING

argon007
Starting Member

38 Posts

Posted - 2008-06-03 : 23:56:33

thank you.

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