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qman
Constraint Violating Yak Guru
442 Posts |
Posted - 2008-10-06 : 14:29:16
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| I was hoping someone could help me out with this query....I want to show companies that have a valid alternate address (joined from another table (alt_address table)).Within the alt_address table, there are records which include null values for address_1, address_2, address_3, city, state, zip, and country. I do not want these records in my result.I am close, just not quite there.....select aa1.company_id, c.company_nameFROM alt_address aa1inner join company c on c.company_id = aa1.company_idWHERE not exists (select * from alt_addresswhere company_id is not null and physical_zip is null and physical_country is null and physical_state is null and physical_address_1 is null and physical_address_2 is null and physical_address_3 is null and physical_city is null)I am expecting 500 or so records to be returned from this query, unfortunately, none come back when run. |
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webfred
Master Smack Fu Yak Hacker
8781 Posts |
Posted - 2008-10-06 : 14:36:53
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| do you mean something like this?select aa1.company_id, c.company_nameFROM alt_address aa1inner join company c on c.company_id = aa1.company_idWHERE aa1.company_id is not null and aa1.physical_zip is not null and aa1.physical_country is not null and aa1.physical_state is not null and aa1.physical_address_1 is not null and aa1.physical_address_2 is not null and aa1.physical_address_3 is not null and aa1.physical_city is not nullGreetingsWebfredPlanning replaces chance by mistake |
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qman
Constraint Violating Yak Guru
442 Posts |
Posted - 2008-10-06 : 14:43:21
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| Yes, I went the easier route originally but I am expecting about 500 records to come back.When I run the select statememnt within my exists statement, 10 records are found.I then expect to run the whole query and 500 minus the 10 will be returned. |
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hanbingl
Aged Yak Warrior
652 Posts |
Posted - 2008-10-06 : 14:43:25
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I assume if all the alt-address parts are null or blank then you want to excludeselect aa1.company_id, c.company_nameFROM alt_address aa1inner join company c on c.company_id = aa1.company_idwhere isnull(physical_zip,'')+isnull(physical_country ,'')+isnull(physical_state ,'')+isnull(physical_address_1 ,'')+isnull(physical_address_2 ,'')+isnull(physical_address_3 ,'')+isnull(physical_city ,'') <> '' |
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hanbingl
Aged Yak Warrior
652 Posts |
Posted - 2008-10-06 : 14:46:57
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Your not exists should look like select aa1.company_id, c.company_nameFROM alt_address aa1inner join company c on c.company_id = aa1.company_idWHERE not exists (select 1 from alt_addresswhere company_id = aa1.company_id and physical_zip is null and physical_country is null and physical_state is nulland physical_address_1 is null and physical_address_2 is null and physical_address_3 is null and physical_city is null) |
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qman
Constraint Violating Yak Guru
442 Posts |
Posted - 2008-10-06 : 14:47:16
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| Hi Hanbingl, you got it.... That worked perfectly!THANKS! |
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