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WindChaser
Posting Yak Master
225 Posts |
Posted - 2008-12-29 : 18:12:51
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| Hi folks.A bit of a rounding issue. This is my statementSelect ID, Amount, Round(Amount,2) as RoundedAmount from Transactions where ID = 7and it returnsID Amount RoundedAmount7 7.69 7.6899999999999995Can anyone tell me what's going on?Thanks! |
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revdnrdy
Posting Yak Master
220 Posts |
Posted - 2008-12-29 : 18:56:08
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| Well at a glance the syntax looks ok. I would presume you may wish to check your datatype. Perhaps you need to look at CAST or CONVERT functions in sql?Otherwise the syntax of the code is correct. It seems to depend on what the datatype of field 'amount' is.Hard to believe that the code would add precision since the original value of amount is 7.69 in your example.r&r |
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WindChaser
Posting Yak Master
225 Posts |
Posted - 2008-12-29 : 19:32:14
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| Data type of the Amount column is real. How 'bout this: Select ID, Amount, Round(Amount,2) as RoundedAmount from Transactions where Amount <> Round(Amount,2) yields the following partial resultsID Amount RoundedAmount1 85.6 85.63 250.4 250.44 92.63 92.6311 92.8 92.812 73.6 73.613 289.6 289.614 523.2 523.216 437.2 437.221 370.56 370.5628 266.02 266.0229 200.63 200.63What the heck is going on?????????? |
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tkizer
Almighty SQL Goddess
38200 Posts |
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WindChaser
Posting Yak Master
225 Posts |
Posted - 2008-12-29 : 20:21:13
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| Well, of course you're right as usual Tara. I performed the query by casting as decimal and everything works fine. But I still can't swallow the fact that Round(7.69, 2) = 7.6899999999999995 . I don't care what type the field is, that's just plain wrong. |
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Michael Valentine Jones
Yak DBA Kernel (pronounced Colonel)
7020 Posts |
Posted - 2008-12-30 : 00:02:04
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quote: Originally posted by WindChaser Well, of course you're right as usual Tara. I performed the query by casting as decimal and everything works fine. But I still can't swallow the fact that Round(7.69, 2) = 7.6899999999999995 . I don't care what type the field is, that's just plain wrong.
No, it is not wrong. You have to realize that REAL and FLOAT are binary numbers, and decimal fractions do not always have an exact representation as binary fractions, so it may be displayed as a repeating decimal.If you are handling ordinary amounts, use DECIMAL data types, or you will be dealing with this issue all the time. Use REAL and FLOAT for scientific calculations or with calculations that use SQL Server trigonometric or math functions.CODO ERGO SUM |
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WindChaser
Posting Yak Master
225 Posts |
Posted - 2008-12-30 : 09:07:41
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quote: Originally posted by Michael Valentine Jones No, it is not wrong. You have to realize that REAL and FLOAT are binary numbers, and decimal fractions do not always have an exact representation as binary fractions, so it may be displayed as a repeating decimal.CODO ERGO SUM
Understood, thanks for that. But I still can't wrap myself around the fact that the Round function can completely disregard the specified limit of digits. If I specify Round(7.69, 2), isn't it inherent to the function to limit itself to 2 digits? |
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Michael Valentine Jones
Yak DBA Kernel (pronounced Colonel)
7020 Posts |
Posted - 2008-12-30 : 09:45:01
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quote: Originally posted by WindChaser
quote: Originally posted by Michael Valentine Jones No, it is not wrong. You have to realize that REAL and FLOAT are binary numbers, and decimal fractions do not always have an exact representation as binary fractions, so it may be displayed as a repeating decimal.CODO ERGO SUM
Understood, thanks for that. But I still can't wrap myself around the fact that the Round function can completely disregard the specified limit of digits. If I specify Round(7.69, 2), isn't it inherent to the function to limit itself to 2 digits?
The round function rounds the value down as requested, but since the output data type is FLOAT, it has to convert it to a FLOAT value that is the closest possible representation in binary.As I said before, you should avoid FLOAT and REAL for ordinary quantities like this.select x, xr = round(x,2), xrr = round(convert(decimal(10,2),x),2)from ( select x = convert(real, 7.69) ) aResults:x xr xrr ------------------------ ----------------------------------------------------- ------------ 7.6900001 7.6899999999999995 7.69(1 row(s) affected) CODO ERGO SUM |
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WindChaser
Posting Yak Master
225 Posts |
Posted - 2008-12-30 : 10:48:15
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| I've converted all relevant columns. Thanks again! |
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