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R
Constraint Violating Yak Guru
328 Posts |
Posted - 2009-05-08 : 05:36:16
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HiI know this is probably very hard to figure out without the full table data, but any pointers would be helpful.In the following statement (with two commented out lines) I see the results I expect. Within these results, all the values for the sg.archived (bit) column display as 0.When I remove the comments though, I get zero rows in my results. I can't figure out why this happens considering the values are all 0 anyway.Can anyone see what I'm doing wrong?SELECT *FROM [tbl_u] u INNER JOIN [tbl_sol] sol ON u.solID = sol.ID INNER JOIN [tbl_ol] ol ON sol.olID = ol.olID INNER JOIN [tbl_si] si ON si.ID = sol.siID LEFT OUTER JOIN [tbl_sgu] sgu ON sgu.uID = u.uID LEFT OUTER JOIN [tbl_sg] sg ON sgu.sgID = sgsgID LEFT OUTER JOIN [tbl_sgs] sgs ON sgs.sgID = sg.sgID LEFT OUTER JOIN [tbl_S] s ON s.sID = sgs.sIDWHERE (u.customerID = 15) AND (u.archived = 0) AND (sg.sgID = @sgID OR @sgID IS NULL) AND (s.sID = @sID OR @sID IS NULL) AND -- removed -- (sg.archived = 0) AND (si.ID = @siID OR @siID IS NULL) AND (ol.olID = @dID OR @dID IS NULL) |
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SwePeso
Patron Saint of Lost Yaks
30421 Posts |
Posted - 2009-05-08 : 06:23:12
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[code]SELECT *FROM [tbl_u] uINNER JOIN [tbl_sol] sol ON u.solID = sol.IDINNER JOIN [tbl_ol] ol ON sol.olID = ol.olIDINNER JOIN [tbl_si] si ON si.ID = sol.siIDLEFT JOIN [tbl_sgu] sgu ON sgu.uID = u.uIDLEFT JOIN [tbl_sg] sg ON sgu.sgID = sg.sgID AND (sg.sgID = @sgID OR @sgID IS NULL) AND (sg.archived = 0)LEFT JOIN [tbl_sgs] sgs ON sgs.sgID = sg.sgIDLEFT JOIN [tbl_S] s ON s.sID = sgs.sID AND (s.sID = @sID OR @sID IS NULL)WHERE u.customerID = 15 AND u.archived = 0 AND (si.ID = @siID OR @siID IS NULL) AND (ol.olID = @dID OR @dID IS NULL)[/code] E 12°55'05.63"N 56°04'39.26" |
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R
Constraint Violating Yak Guru
328 Posts |
Posted - 2009-05-08 : 06:38:55
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| PesoYou are a T-SQL superstar - that works like a charm!Please tell me, what is the difference in applying the filter in the JOIN instead of in the WHERE clause? Why does SQL produce different results for each? |
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SwePeso
Patron Saint of Lost Yaks
30421 Posts |
Posted - 2009-05-08 : 06:40:59
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Because of the outer joins (LEFT JOIN).Thank you for your feedback. E 12°55'05.63"N 56°04'39.26" |
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R
Constraint Violating Yak Guru
328 Posts |
Posted - 2009-05-08 : 08:38:33
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| Ah yes, I've just done some testing based on your feedback. Here's my findings for anyone suffering the same problem.It happens because the LEFT JOIN creates NULLs in the results, so by adding the WHERE clause filter, we end up removing those NULLs, when we actually needed to see them. If we JOIN the table and remove the 0 values at that stage, the results are unaffected.Now that that's clear, I can once again have my sanity back...Thanks Peso! :-D |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2009-05-09 : 05:14:16
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quote: Originally posted by R Ah yes, I've just done some testing based on your feedback. Here's my findings for anyone suffering the same problem.It happens because the LEFT JOIN creates NULLs in the results, so by adding the WHERE clause filter, we end up removing those NULLs, when we actually needed to see them. If we JOIN the table and remove the 0 values at that stage, the results are unaffected.Now that that's clear, I can once again have my sanity back...Thanks Peso! :-D
this article explains ithttp://weblogs.sqlteam.com/jeffs/archive/2007/05/14/60205.aspx |
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R
Constraint Violating Yak Guru
328 Posts |
Posted - 2009-05-09 : 05:30:10
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| "Never reference OUTER JOIN-ed tables in your WHERE clause."That's a really informative article. Thanks visakh16 |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2009-05-09 : 05:34:22
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| welcome |
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