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Best Approach

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Topic

Rayman
Starting Member

39 Posts

Posted - 2010-09-22 : 15:03:01

I have the following table with the data:

Database_date

11/30/08 1:52 AM
12/31/08 9:22 AM
3/17/08 11:22 AM
1/4/09 11:22 PM

I would like to determine how to produce the sql code to display the information by the following output;

Month AM PM
1 November YES NO
2 December NO YES
3 March YES NO
4 January NO YES

Any suguestions would be appreciated. Thank you

Terry L King

jimf
Master Smack Fu Yak Hacker

2875 Posts

Posted - 2010-09-22 : 15:09:36

DECLARE @Table TABLE (database_date datetime)

insert into @Table

SELECT '11/30/08 1:52 AM' UNION
SELECT '12/31/08 9:22 AM' UNION
SELECT '3/17/08 11:22 AM' UNION
SELECT '1/4/09 11:22 PM'

SELECT datename(month,database_date) as [Month]
,CASE WHEN datepart(hour,database_date) >=12 THEN 'YES' ELSE 'NO' END as PM
,CASE WHEN datepart(hour,database_date) <12 THEN 'YES' ELSE 'NO' END as AM

FROM @table

Jim

Everyday I learn something that somebody else already knew

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2010-09-23 : 12:37:20

I assume the december values in sample is a typo as i see time as AM but it has just opposite values in output

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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