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archana23
Yak Posting Veteran
89 Posts |
Posted - 2013-10-09 : 16:09:39
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Hi,Right now i am using this expression to get the time difference between two times.{%Z.elapsed.time(@AK.VD.depart.date,@AK.VD.depart.time,@AK.VD.depart.date,@DV.VD.arrival.time,"hh.hh")*60} as [LOS (min)]When Arrival time and depart time both are on same day above expression working to get the diference . But if arrival date 2013-09-20 00:00:00.000 and arrival time 0800and depart date 2013-09-21 00:00:00.000 and depart time 0050when i calculate the time difference(using above expression) between these two i am getting -429.60 which is wrong. i have to get around 990.How can i overcome this problem.Can any one help me on this ?Thank you so muchArchana |
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James K
Master Smack Fu Yak Hacker
3873 Posts |
Posted - 2013-10-09 : 16:36:37
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{%Z.elapsed.time(@AK.VD.depart.date,@AK.VD.depart.time,@AK.VD.depart.date,@DV.VD.arrival.time,"hh.hh")*60} as [LOS (min)]The expression you are using doesn't look familiar syntax for SQL Server. If you are using another RDBMS system, you would get better and faster answers at a forum specific to that system. This forum is a Microsoft SQL Server forum. |
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