Last version of each budget! - SQL Server Forums

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Last version of each budget!

Author

Topic

martalex
Starting Member

17 Posts

Posted - 2004-03-11 : 20:18:55

I have the following table.

BudgetItem(BudgetItem_id, budget_id, cash, version)
1, 1, 10, 1
2, 1, 15, 2
3, 2, 25, 1
4, 2, 35, 2
5, 2, 20, 3

How could I retrieve only the last version of each budget?
2, 1, 15, 2
5, 2, 20, 3

jsmith8858
Dr. Cross Join

7423 Posts

Posted - 2004-03-11 : 20:22:35

you have no definition of "last" in your data.

- Jeff

martalex
Starting Member

17 Posts

Posted - 2004-03-11 : 20:47:28

Sorry, last means the the highest version number.

MichaelP
Jedi Yak

2489 Posts

Posted - 2004-03-11 : 21:13:47

Like so:


CREATE TABLE #BudgetItem(BudgetItem_id INT, budget_id INT, cash INT, version INT)

INSERT INTO #BudgetItem(BudgetItem_id, budget_id, cash, version) VALUES(1, 1, 10, 1)

INSERT INTO #BudgetItem(BudgetItem_id, budget_id, cash, version) VALUES(2, 1, 15, 2)

INSERT INTO #BudgetItem(BudgetItem_id, budget_id, cash, version) VALUES(3, 2, 25, 1)

INSERT INTO #BudgetItem(BudgetItem_id, budget_id, cash, version) VALUES(4, 2, 35, 2)

INSERT INTO #BudgetItem(BudgetItem_id, budget_id, cash, version) VALUES(5, 2, 20, 3)

SELECT b.BudgetItem_id, b.budget_id, b.cash, b.version
FROM #BudgetItem b
WHERE b.version = (SELECT MAX(version) FROM #BudgetItem WHERE budget_id = b.budget_id)

DROP TABLE #BudgetItem

In the future, it's really helpful if you can post CREATE TABLE statements like I did above. It makes solving the problem that much quicker.

Enjoy!

Michael

<Yoda>Use the Search page you must. Find the answer you will.</Yoda>

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