calculation within a column - SQL Server Forums

Please start any new threads on our new site at https://forums.sqlteam.com. We've got lots of great SQL Server experts to answer whatever question you can come up with.

All Forums

General SQL Server Forums

New to SQL Server Programming

calculation within a column

Author

Topic

NhanLe
Starting Member

3 Posts

Posted - 2008-10-27 : 07:23:05

Date happening duration
11/11/2008 online 8:00
11/11/2008 offline1 1:00
11/11/2008 offline2 2:10
11/11/2008 offline1 0:20
12/11/2008 online 16:00
12/11/2008 offline2 0:30

How can I calculate for every day the duration of the online time?
online - (sum(offline1)+sum(offline2)

Result should be a resume for every day:
date RealOnline
11/11/2008 4:30
12/11/2008 15:30

Looking forward for your help

Thanks
Nhan

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2008-10-27 : 07:28:54

[code]SELECT DATEADD(dd,DATEDIFF(dd,0,Date),0),
SUM(CASE WHEN happening ='online' THEN duration ELSE 0 END)-(SUM(CASE WHEN happening ='offline1' THEN duration ELSE 0 END)+SUM(CASE WHEN happening ='offline2' THEN duration ELSE 0 END))
FROM YourTable
GROUP BY DATEADD(dd,DATEDIFF(dd,0,Date),0)[/code]

NhanLe
Starting Member

3 Posts

Posted - 2008-10-27 : 07:51:19

dear visakh16,

Thank you for the extremely fast response, looks very neat.
Yet I've mistaken in the forum. I need the code for access 2003.

U're great

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2008-10-27 : 07:59:25

quote:
Originally posted by NhanLe

dear visakh16,

Thank you for the extremely fast response, looks very neat.
Yet I've mistaken in the forum. I need the code for access 2003.

U're great

then please post this in access forum.

Subscribe to SQLTeam.com

SQLTeam.com Articles via RSS

SQLTeam.com Weblog via RSS

- Advertisement -

Resources