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OPENXML relational data query

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Topic

neophyte226
Starting Member

7 Posts

Posted - 2009-08-03 : 14:57:30

What am I missing in order to return multiple values for a column off of the record number?

DECLARE @h int
DECLARE @x xml
set @x = (select cast('<test>
<date>10-02-2006</date>
<rec-number>9</rec-number>
<tranDetail>
<name>Art</name>
<name>John</name>
<name>Todd</name>
</tranDetail>
</test>
' as xml))
EXEC sp_xml_preparedocument @h output, @x

select * from openxml(@h, 'test', 2)
with (date varchar(20) 'date',
[rec-number] int 'rec-number',
[name] varchar(10) 'tranDetail/name'
)
EXEC sp_xml_removedocument @h

returns
date rec-number name
10-02-2006 9 Art

but i'm looking for
date rec-number name
10-02-2006 9 Art
10-02-2006 9 John
10-02-2006 9 Todd

SwePeso
Patron Saint of Lost Yaks

30421 Posts

Posted - 2009-08-03 : 15:02:59

Are you using SQL Server 2000 or SQL Server 2005?

N 56°04'39.26"
E 12°55'05.63"

neophyte226
Starting Member

7 Posts

Posted - 2009-08-03 : 15:24:34

Thanks for the interest and it's SQL Server 2005. I have a data dump in xml format I need to parse and maybe I should be using xml schema?

SwePeso
Patron Saint of Lost Yaks

30421 Posts

Posted - 2009-08-03 : 15:37:23

[code]DECLARE @x xml

set @x = '<test>
<date>10-02-2006</date>
<rec-number>9</rec-number>
<tranDetail>
<name>Art</name>
<name>John</name>
<name>Todd</name>
</tranDetail>
</test>'

SELECT t.n.value('date[1]', 'datetime') AS [date],
t.n.value('rec-number[1]', 'varchar(12)') AS [rec-number],
n.n.value('.', 'varchar(20)') AS name
FROM @x.nodes('//test') AS t(n)
cross apply t.n.nodes('tranDetail/name') AS n(n)code]

N 56°04'39.26"
E 12°55'05.63"

neophyte226
Starting Member

7 Posts

Posted - 2009-08-03 : 16:37:12

Thanks but I'm still having trouble understanding the pivot record vs the attributes. Below is a sample of the schema I'm working with and I get lost as the the schema gets more tags.

DECLARE @h int --9272 records
DECLARE @x xml
set @x = '<xml>
<records>
<record>
<rec-number>2</rec-number>
<contributors>
<authors>
<author>Adam</author>
<author>Barry</author>
<author>Cary</author>
</authors>
</contributors>
</record>
<record>
<rec-number>6</rec-number>
<contributors>
<authors>
<author>Adam</author>
<author>Eric</author>
<author>John</author>
</authors>
</contributors>
</record>
<record>
<rec-number>8</rec-number>
<contributors>
<authors>
<author></author>
</authors>
</contributors>
</record>
</records>
</xml>
'

select
t.n.value('rec-number[1]', 'int') as [rec-number]
, n.n.value('.', 'varchar(50)') as author
from
@x.nodes('/xml/records/record') as t(n)
cross apply t.n.nodes('//author') as n(n)
order by 1, 2

SwePeso
Patron Saint of Lost Yaks

30421 Posts

Posted - 2009-08-04 : 00:38:19

[code]DECLARE @h int --9272 records
DECLARE @x xml
set @x = '
<xml>
<records>
<record>
<rec-number>2</rec-number>
<contributors>
<authors>
<author>Adam</author>
<author>Barry</author>
<author>Cary</author>
</authors>
</contributors>
</record>
<record>
<rec-number>6</rec-number>
<contributors>
<authors>
<author>Adam</author>
<author>Eric</author>
<author>John</author>
</authors>
</contributors>
</record>
<record>
<rec-number>8</rec-number>
<contributors>
<authors>
<author></author>
</authors>
</contributors>
</record>
</records>
</xml>'

select t.n.value('rec-number[1]', 'int') as [rec-number]
, n.n.value('.', 'varchar(50)') as author
from @x.nodes('//xml/records/record') as t(n)
cross apply t.n.nodes('contributors/authors/author') as n(n)
order by 1,
2[/code]

N 56°04'39.26"
E 12°55'05.63"

neophyte226
Starting Member

7 Posts

Posted - 2009-08-04 : 09:28:34

Thank you very much. I guess I need to do some more reading on XML in SQL server.

weipublic
Starting Member

19 Posts

Posted - 2009-08-06 : 01:31:53

Hi neophyte226, following should work for your original requirements.


select * from openxml(@h, '//name', 2)
with (date varchar(20)  '../../date',
     [rec-number] int   '../../rec-number',
     [name] varchar(10) 'text()'
     )

SwePeso
Patron Saint of Lost Yaks

30421 Posts

Posted - 2009-08-06 : 02:25:12

Since OP is using SQL Server 2005, he better use the new ways to deal with XML data.

N 56°04'39.26"
E 12°55'05.63"

weipublic
Starting Member

19 Posts

Posted - 2009-08-08 : 13:04:31

Thanks Peso!!!

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