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getur.srikanth@gmail.com
Yak Posting Veteran
77 Posts |
Posted - 2009-09-23 : 10:46:06
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I have couple records like this. How can delete only RoldID='1E36A840-2EBB-44EC-8861-0E3D262AC676' records ,If they already have RoldID='0B54F223-E0D4-4CFC-84C3-7C98C1BFC6DA' in that table? |
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rocknpop
Posting Yak Master
201 Posts |
Posted - 2009-09-23 : 11:20:35
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| IF EXISTS(SELECT 1 FROM YOURTABLE WHERE RoldID='0B54F223-E0D4-4CFC-84C3-7C98C1BFC6DA')DELETE FROM YOURTABLE WHERE RoldID='1E36A840-2EBB-44EC-8861-0E3D262AC676'--------------------Rock n Roll with SQL |
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getur.srikanth@gmail.com
Yak Posting Veteran
77 Posts |
Posted - 2009-09-23 : 11:47:39
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| How can I get number of user count , Who have both roles.? |
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rocknpop
Posting Yak Master
201 Posts |
Posted - 2009-09-23 : 12:15:37
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| SELECT TABLE.UserId,COUNT(*)OVER()AS TOTALCOUNT FROM TABLE INNER JOIN (SELECT NAME FROM TABLE WHERE ROLE=2) T1 ONTABLE.NAME=T1.NAME WHERE ROLE=1--------------------Rock n Roll with SQL |
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getur.srikanth@gmail.com
Yak Posting Veteran
77 Posts |
Posted - 2009-09-24 : 15:28:39
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| DECLARE @UID uniqueidentifierSELECT TOP 1 @UID=dbo.aspnet_UsersInRoles.UserId FROM dbo.aspnet_UsersInRoles INNER JOIN(SELECT UserId FROM dbo.aspnet_UsersInRoles WHERE ROLEID='0b54f223-e0d4-4cfc-84c3-7c98c1bfc6da') T1 ONdbo.aspnet_UsersInRoles.UserId=T1.UserId WHERE ROLEID='1e36a840-2ebb-44ec-8861-0e3d262ac676'delete from dbo.aspnet_UsersInRoles where userid=@UID and RoleID='1e36a840-2ebb-44ec-8861-0e3d262ac676'I am able to delete only one record. How can i delete all records? Whats wrong in query? |
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rocknpop
Posting Yak Master
201 Posts |
Posted - 2009-09-25 : 09:30:29
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| Do you have an identity column in your table. If yes then you can use this, here Id is the identity:Delete From dbo.aspnet_UsersInRoles Where Id In (SELECT dbo.aspnet_UsersInRoles.Id FROM dbo.aspnet_UsersInRoles AS U1 INNER JOINdbo.aspnet_UsersInRoles AS U2 ON U1.UserId=U2.UserIdWHERE U1.ROLEID='1e36a840-2ebb-44ec-8861-0e3d262ac676'AND U2.ROLEID='0b54f223-e0d4-4cfc-84c3-7c98c1bfc6da')--------------------Rock n Roll with SQL |
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