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NguyenL71
Posting Yak Master
228 Posts |
Posted - 2009-12-22 : 21:32:18
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| I need to extract only the first part of email address of the entire string. Sampledata and desire results are below. Thank you in advance for your help.IF OBJECT_ID('Tempdb.dbo.#Temp', 'u') IS NOT NULL DROP TABLE #Temp GOCREATE TABLE #Temp ( VendId INT NULL, Email VARCHAR(100) NULL)GOINSERT INTO dbo.#Temp(VendId, Email)VALUES (1, 'sam.hantosh@gmail.com')INSERT INTO dbo.#Temp(VendId, Email)VALUES (2, 'teammerrick6@yahoo.com#mailto:teammerrick6@yahoo.com#')INSERT INTO dbo.#Temp(VendId, Email)VALUES (3, '')INSERT INTO dbo.#Temp(VendId, Email)VALUES (4, 'jeff@blackhawkadvisors.net#mailto:jeff@blackhawkadvisors.net#')INSERT INTO dbo.#Temp(VendId, Email)VALUES (5, 'jDPall3@msn.com#mailto:DPall3@msn.com#')go SELECT * FROM #Temp; GO VendId Email----------- --------------------------------------------------------------1 sam.hantosh@gmail.com2 teammerrick6@yahoo.com#mailto:teammerrick6@yahoo.com#3 4 jeff@blackhawkadvisors.net#mailto:jeff@blackhawkadvisors.net#5 jDPall3@msn.com#mailto:DPall3@msn.com# -- Rules: Extract only the first part of the email. Below is show desire results. SELECT VendId ,Email ,LEFT(Email, CHARINDEX('#', Email)) --,SUBSTRING(Email, 1, CHARINDEX('#', Email) - 1) --,LEFT(Email, CHARINDEX('#', Email)-1) FROM #Temp -- Desire results:VendId Email----------- ----------------------1 sam.hantosh@gmail.com2 teammerrick6@yahoo.com3 4 jeff@blackhawkadvisors.net5 jDPall3@msn.com |
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2009-12-22 : 21:43:44
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[code]SELECT VendId ,Email ,LEFT(Email, CHARINDEX('#', Email + '#') - 1)from #Temp[/code] KH[spoiler]Time is always against us[/spoiler] |
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NguyenL71
Posting Yak Master
228 Posts |
Posted - 2009-12-22 : 22:30:26
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Thank you so much.quote: Originally posted by khtan
SELECT VendId ,Email ,LEFT(Email, CHARINDEX('#', Email + '#') - 1)from #Temp KH[spoiler]Time is always against us[/spoiler]
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