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roco
Starting Member
9 Posts |
Posted - 2010-02-04 : 04:45:02
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| Hello again,I forgot to ask about this. What I don't understand is why I don't get unique rows from this sql even though I use the max function.With Recs AS( select max(tr.rid) as rid,tr.del,max(tr.deldate) as deldate,max(tr.credate) as credate,max(tr.cbui) as cbui,max(tr.res) as res,max(y.lu) as lu,max(x.cdate) as cdate from tr inner join tx x on x.rid = tr.rid and x.mmqid = 1 and x.liid = 2 inner join ty y on y.liid = x.liid group by x.cdate,tr.rid,tr.del)select * into #tempRec from Recs where RowNumber Between 1 and 10With this sql I get more than one row regarding the tr.rid when I only want unique.Hope you can help me out.Thanks again! |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2010-02-04 : 04:46:28
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| it just gives you maximum values from other columns for each group of x.cdate,tr.rid,tr.del value. the values returned wont necessarily be the ones in the same row of cte |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2010-02-04 : 04:50:21
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do you need this?select columns...from(select row_number() over (partition by tr.rid order by tr.credate desc) as seq,tr.rid as rid,tr.del,tr.deldate as deldate,tr.credate as credate,tr.cbui as cbui,tr.res as res,y.lu as lu,x.cdate as cdate from tr inner join tx x on x.rid = tr.rid and x.mmqid = 1 and x.liid = 2 inner join ty y on y.liid = x.liid )twhere seq=1 |
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roco
Starting Member
9 Posts |
Posted - 2010-02-04 : 05:14:53
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| What I need is what you helped me with, to get unique rows on tr.rid but also with rownumber incrementing for each row I get so that I can use it for paging purpose. Do you know what I mean? |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2010-02-04 : 05:20:05
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quote: Originally posted by roco What I need is what you helped me with, to get unique rows on tr.rid but also with rownumber incrementing for each row I get so that I can use it for paging purpose. Do you know what I mean?
ok the rownumber should be based on what order? order of trid? |
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roco
Starting Member
9 Posts |
Posted - 2010-02-04 : 05:22:42
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| So I would need the sql below to return unique rows regarding tr.rid and an incremented rownumber for each row.Hope I am being clear.select columns...from(select row_number() over (partition by tr.rid order by x.cdate desc) as seq,tr.rid as rid,tr.del,tr.deldate as deldate,tr.credate as credate,tr.cbui as cbui,tr.res as res,y.lu as lu,x.cdate as cdate from tr inner join tx x on x.rid = tr.rid and x.mmqid = 1 and x.liid = 2 inner join ty y on y.liid = x.liid )twhere seq=1 |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2010-02-04 : 05:24:09
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anyways here you go:-select rid,del,deldate,credate,cbui,res,lu,cdatefrom(select row_number() over (order by <your ordering field here>) as rn,rid,del,deldate,credate,cbui,res,lu,cdatefrom(select row_number() over (partition by tr.rid order by tr.credate desc) as seq,tr.rid as rid,tr.del,tr.deldate as deldate,tr.credate as credate,tr.cbui as cbui,tr.res as res,y.lu as lu,x.cdate as cdate from tr inner join tx x on x.rid = tr.rid and x.mmqid = 1 and x.liid = 2 inner join ty y on y.liid = x.liid )twhere seq=1)rwhere rn between @start and @end |
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roco
Starting Member
9 Posts |
Posted - 2010-02-04 : 05:30:45
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| I guess the rownumber shuld be based on the tr.rid since these should be unique. |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2010-02-04 : 05:37:08
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quote: Originally posted by roco I guess the rownumber shuld be based on the tr.rid since these should be unique.
then fill in in place holder in last suggestion and see |
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roco
Starting Member
9 Posts |
Posted - 2010-02-04 : 05:46:14
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| I think I just missed your last post. I have tried your last post out and I think it works fine! Thanks a lot for helping me out! Hopefully I will get this to work in the context where I need to use it and have no more questions regarding this specific topic:) Thanks again! |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2010-02-04 : 05:52:08
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you're welcome no worries. let us know if you face any more issues |
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