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blued
Starting Member
9 Posts |
Posted - 2011-09-22 : 03:02:39
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| Hi all,I'm trying to create a function that will generate a random string of 5 characters long based on a 6 digit number. For example SELECT MyRandFunction(123456)Returns PTHGYSELECT MyRandFunction(654321)Returns UYTHENext time I run the string generator I expect to see the same values for the same numbers I use. The reason is I need to re use the random string on a per number basis.Has anyone done something similar using the RAND() function or similar? |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2011-09-22 : 04:11:22
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| if its random how will return the same value?------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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blued
Starting Member
9 Posts |
Posted - 2011-09-25 : 03:28:10
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| Sorry I wasn't clear, it needs to generate a 5 character string from a 6 digit number. When I say random I just mean that it doesn't matter what the 5 characters are so long as it is unique to the 6 digit number.If you see this thread - http://stackoverflow.com/questions/1324063/generating-random-strings-with-t-sqlThe first reply is similar to what I need but I can't get it to work for a 5 character string from a 6 digit number. |
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SwePeso
Patron Saint of Lost Yaks
30421 Posts |
Posted - 2011-09-25 : 18:03:06
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[code]DECLARE @Value INT = 654321SELECT CHAR(65 + Value % 26) + Digit2 + Digit3 + Digit4 + Digit5FROM ( SELECT Value / 26 AS Value, CHAR(65 + Value % 26) AS Digit2, Digit3, Digit4, Digit5 FROM ( SELECT Value / 26 AS Value, CHAR(65 + Value % 26) AS Digit3, Digit4, Digit5 FROM ( SELECT Value / 26 AS Value, CHAR(65 + Value % 26) AS Digit4, Digit5 FROM ( SELECT @Value / 26 AS Value, CHAR(65 + @Value % 26) AS Digit5 ) AS d ) AS d ) AS d ) AS d[/code] N 56°04'39.26"E 12°55'05.63" |
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blued
Starting Member
9 Posts |
Posted - 2011-09-25 : 19:41:28
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| Many thanks SwePeso, this is exactly what I was looking for. |
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