Please start any new threads on our new 
    site at https://forums.sqlteam.com.  We've got lots of great SQL Server
    experts to answer whatever question you can come up with. 
    
        
            
                
                    
                        
                            
                                | Author | 
                                
                                 Topic  | 
                             
                            
                                    | 
                                         BillEdd 
                                        Starting Member 
                                         
                                        
                                        12 Posts  | 
                                        
                                        
                                            
                                            
                                             Posted - 2015-03-18 : 13:06:02
                                            
  | 
                                             
                                            
                                            | I need to return a record for each type in my IN clause and not just the records that have a count of > 0.  Not sure how to do this.  Desired sample resultsMFN    0PRM   10BCO    0Select o.ORD_TYPE, count(*) as NumberOfOrdersFrom Orders ojoin Emps r on r.EmpNo = o.ORD_Emp_NOjoin Order_Type_Groups g on g.Ord_TYPE = o.ORD_TypeWhere year(ORD_DATE) = '2014'      and ORD_TYPE in ('MFN', 'BCO', 'PRM')      and left(o.ORD_Acct_Num ,3)='NPC'      group by ORD_TYPEThanks for your help | 
                                             
                                         
                                     | 
                             
       
                            
                       
                          
                            
                                    | 
                                     tkizer 
                                    Almighty SQL Goddess 
                                     
                                    
                                    38200 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2015-03-18 : 13:10:03
                                          
  | 
                                         
                                        
                                          | Not enough info, but you could try LEFT JOIN.Tara KizerSQL Server MVP since 2007http://weblogs.sqlteam.com/tarad/  | 
                                         
                                        
                                            | 
                                         
                                       
                                     | 
                                   
                            
                       
                          
                            
                                    | 
                                     BillEdd 
                                    Starting Member 
                                     
                                    
                                    12 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2015-03-18 : 14:24:00
                                          
  | 
                                         
                                        
                                          | Tara:Thanks for your reply.  What more info do you need? And if possible based on the info I provided, could you please provide an example using your suggestion?Thanks  | 
                                         
                                        
                                            | 
                                         
                                       
                                     | 
                                   
                            
                       
                          
                            
                                    | 
                                     tkizer 
                                    Almighty SQL Goddess 
                                     
                                    
                                    38200 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2015-03-18 : 14:27:27
                                          
  | 
                                         
                                        
                                          | We'd need to see sample data from the tables involved that illustrate the issue.left join Order_Type_Groups g on g.Ord_TYPE = o.ORD_TypeTara KizerSQL Server MVP since 2007http://weblogs.sqlteam.com/tarad/  | 
                                         
                                        
                                            | 
                                         
                                       
                                     | 
                                   
                            
                       
                          
                            
                                    | 
                                     BillEdd 
                                    Starting Member 
                                     
                                    
                                    12 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2015-03-18 : 15:41:44
                                          
  | 
                                         
                                        
                                          | Tara:Thanks for your reply. Not sure I can provide that without altering it a lot for data confidentiality reasons.  I tried your suggested join but got the same results as I did without it.To try to illustrate, the Orders table has different types of orders whose o.ord_type is listed in the Order_Type_Groups table.  The Emps table join is used to just get orders for a certain type of salesperson.  That should have read:join Emps on r.EmpNo = o.ORD_Emp_No and r.EmpStatus = 'A'Not sure if this helps or not.  In my example there were no orders for ORD_Type of MFN or ORD_Type of BCO.  There were 10 orders for Ord_Type of PRM.If this is still not enough info then I will close the post and say thanks for your help working with what you had to work with.ThanksBill  | 
                                         
                                        
                                            | 
                                         
                                       
                                     | 
                                   
                            
                       
                          
                            
                                    | 
                                     tkizer 
                                    Almighty SQL Goddess 
                                     
                                    
                                    38200 Posts  | 
                                    
                                      
                                     | 
                                   
                            
                       
                          
                            
                                    | 
                                     tkizer 
                                    Almighty SQL Goddess 
                                     
                                    
                                    38200 Posts  | 
                                    
                                      
                                     | 
                                   
                            
                       
                          
                            
                                    | 
                                     madhivanan 
                                    Premature Yak Congratulator 
                                     
                                    
                                    22864 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2015-03-19 : 02:47:47
                                          
  | 
                                         
                                        
                                          | Can you try this?Select o.ORD_TYPE, count(*) as NumberOfOrdersFrom Orders ojoin Emps r on r.EmpNo = o.ORD_Emp_NOleft join Order_Type_Groups g on g.Ord_TYPE = o.ORD_Type and ORD_TYPE in ('MFN', 'BCO', 'PRM')Where year(ORD_DATE) = '2014' and left(o.ORD_Acct_Num ,3)='NPC' group by ORD_TYPEMadhivananFailing to plan is Planning to fail  | 
                                         
                                        
                                            | 
                                         
                                       
                                     | 
                                   
                            
                            
                                | 
                                    
                                      
                                     
                                    
                                 | 
                             
                         
                     | 
                 
             
         |   
     
     
            
              
	     |  
		
			
     
          
		 |