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dukey07
Starting Member
16 Posts |
Posted - 2003-08-08 : 12:16:32
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| I'm trying to get a count of the occurences of a sub string within a string. Is this the the way to do it?Declare @test varchar(255)Select @test = 'blah blah@bla bla bla@'Select Len(@test) - Len(Replace(@test,'@','')) |
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nr
SQLTeam MVY
12543 Posts |
Posted - 2003-08-08 : 12:42:00
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| It's the easiest and probably fastest.==========================================Cursors are useful if you don't know sql.DTS can be used in a similar way.Beer is not cold and it isn't fizzy. |
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jsmith8858
Dr. Cross Join
7423 Posts |
Posted - 2003-08-08 : 14:54:42
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uh uh ... here comes Jay with a "set-based" method ... I can feel it .... - Jeff |
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setbasedisthetruepath
Used SQL Salesman
992 Posts |
Posted - 2003-08-08 : 14:58:26
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That hurts ... placing set-based in quotes as though it's not "real" or "valid" ... Jonathan{0} |
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setbasedisthetruepath
Used SQL Salesman
992 Posts |
Posted - 2003-08-08 : 14:58:59
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| Don't forget to divide by the length of the substring.Jonathan{0} |
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jsmith8858
Dr. Cross Join
7423 Posts |
Posted - 2003-08-08 : 15:59:07
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Actually, you're right, i mis-used the quotes! I meant to use them like this:Jay is a "well-respected" and "accomplished" guy. - Jeff |
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