binary_checksum can in some case give same checksum, see bol.This will give records that are1. different2. in table a but not in table b, and vice versaselect	a.[order id],        a.col1, a.col2,,,,	b.[order id],        b.col1, b.col2,,,,from	( select *, binary_checksum(*) as bchk from a ) as a	full join	( select *, binary_checksum(*) as bchk from b ) as b		on a.[order id] = b.[order id]where	a.bchk <> b.bchk	or a.bchk + b.bchk is null
rockmoose