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nathans
Aged Yak Warrior
938 Posts |
 Posted - 2004-12-30 : 15:07:30
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| Hey guys,Im just inetrested how others would approach this issue.Have a resultset with names, each ending in an integer.Nathan Skerl 1Nathan Skerl 2John Smith 1...I want to select the full name, and remove the trailing integer.Currently:SELECT REPLACE(REPLACE(partner_name, '1', ''), '2', '')Feels dirty though... :)Any thoughts?Assume the format is [FName][Space][LName][Space][Integer] |
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ehorn
Master Smack Fu Yak Hacker
1632 Posts |
Posted - 2004-12-30 : 15:15:26
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Lots of ways to do this - here is one:declare @name varchar(40)set @name = 'Nathan Skerl 1'select left(@name,len(@name)-charindex(' ',reverse(@name),1)) |
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nathans
Aged Yak Warrior
938 Posts |
Posted - 2004-12-30 : 15:19:00
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| Thats what im talking about... I love this stuff. Well done ehorn! |
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spirit1
Cybernetic Yak Master
11752 Posts |
Posted - 2004-12-30 : 15:31:02
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you could also do:select left(@name, patindex('%[0-9]%', @name)-2)Go with the flow & have fun! Else fight the flow  |
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Elegant way to remove characters?