How to select SUM from another table

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Transact-SQL (2000)

How to select SUM from another table

Author

Topic

chexone
Starting Member

6 Posts

Posted - 2007-07-27 : 11:28:55

Hi!

Look at this simple query.

SELECT a.ID,
(select SUM(b.amount) FROM tableB b WHERE b.paid = 0) AS totalDue
FROM tableA a

This will return the total sum of all records in tableB, for each result.

How do I make it return only the total due for each record. In other words, what't the correct syntax for this:

SELECT a.ID,
(select SUM(b.amount) FROM tableB b WHERE b.paid = 0 AND b.ID= #currentID#) AS totalDue
FROM tableA a

Thanks!

nr
SQLTeam MVY

12543 Posts

Posted - 2007-07-27 : 11:50:35

SELECT a.ID,
(select SUM(b.amount) FROM tableB b WHERE b.paid = 0 AND b.ID= a.ID) AS totalDue
FROM tableA a

==========================================
Cursors are useful if you don't know sql.
DTS can be used in a similar way.
Beer is not cold and it isn't fizzy.

chexone
Starting Member

6 Posts

Posted - 2007-07-27 : 12:00:28

Brilliant! Thank you!!

SwePeso
Patron Saint of Lost Yaks

30421 Posts

Posted - 2007-07-27 : 15:49:42

[code]SELECT a.ID,
SUM(ISNULL(b.Amount, 0)) AS TotalDue
FROM TableA AS a
LEFT JOIN TableB AS b ON b.ID = a.ID AND b.Paid = 0
GROUP BY a.ID[/code]

E 12°55'05.25"
N 56°04'39.16"

EDIT: nr found my sloppy work

nr
SQLTeam MVY

12543 Posts

Posted - 2007-07-27 : 16:10:54

That would need a group by.

==========================================
Cursors are useful if you don't know sql.
DTS can be used in a similar way.
Beer is not cold and it isn't fizzy.

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