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danyeung
Posting Yak Master
102 Posts |
 Posted - 2007-10-31 : 12:39:49
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| I tried this and worked. It printed out 'somewhere'declare @str as char(20)set @str = 'region - somewhere'print substring(@str, 10, len(@str) - 9)Why I used the same syntax in a where clause and it didn't work? I got an error "Invalid length parameter passed to the SUBSTRING function."WHERE substring(nvchrName, 10, LEN(nvchrName) - 9) = nvchrRegionThanks.DanYeung |
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2007-10-31 : 12:44:14
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your string in nvchrName is less than 10
KH[spoiler]Time is always against us[/spoiler] |
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danyeung
Posting Yak Master
102 Posts |
Posted - 2007-10-31 : 13:40:04
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| You are right. Thanks.DanYeung |
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nr
SQLTeam MVY
12543 Posts |
Posted - 2007-10-31 : 13:42:03
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| len excludes the space charaters at the end of the string. Substring errors if there is a length less than zeo.The error you are gettnig means there is at least one row in the table with that column too short for the substring.why notWHERE substring(nvchrName, 10, 1000) = nvchrRegion==========================================Cursors are useful if you don't know sql.DTS can be used in a similar way.Beer is not cold and it isn't fizzy. |
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madhivanan
Premature Yak Congratulator
22864 Posts |
Posted - 2007-11-01 : 02:34:35
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| ornvchrName like '%'+nvchrRegion??MadhivananFailing to plan is Planning to fail |
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Why LEN function does not work in SUBSTRING?